1050543131 has 4 divisors (see below), whose sum is σ = 1146047064. Its totient is φ = 955039200.

The previous prime is 1050543127. The next prime is 1050543133. The reversal of 1050543131 is 1313450501.

1050543131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1050543131 - 2² = 1050543127 is a prime.

It is a super-2 number, since 2×1050543131² = 2207281740182566322, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1050543097 and 1050543106.

It is not an unprimeable number, because it can be changed into a prime (1050543133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 47751950 + ... + 47751971.

It is an arithmetic number, because the mean of its divisors is an integer number (286511766).

Almost surely, 2^1050543131 is an apocalyptic number.

1050543131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

1050543131 is a deficient number, since it is larger than the sum of its proper divisors (95503933).

1050543131 is an equidigital number, since it uses as much as digits as its factorization.

1050543131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 95503932.

The product of its (nonzero) digits is 900, while the sum is 23.

The square root of 1050543131 is about 32412.0831018310. The cubic root of 1050543131 is about 1016.5715762477.

Adding to 1050543131 its reverse (1313450501), we get a palindrome (2363993632).

The spelling of 1050543131 in words is "one billion, fifty million, five hundred forty-three thousand, one hundred thirty-one".