Base | Representation |
---|---|
bin | 11110100111100100001… |
… | …11001110101010110111 |
3 | 10201120111001120120202011 |
4 | 33103302013032222313 |
5 | 114214031201022331 |
6 | 2123144151425051 |
7 | 136002245316406 |
oct | 17236207165267 |
9 | 3646431516664 |
10 | 1052034001591 |
11 | 37618a8494a1 |
12 | 14ba84085187 |
13 | 7828b5590b1 |
14 | 38cc0d6363d |
15 | 1c5749883b1 |
hex | f4f21ceab7 |
1052034001591 has 2 divisors, whose sum is σ = 1052034001592. Its totient is φ = 1052034001590.
The previous prime is 1052034001589. The next prime is 1052034001597. The reversal of 1052034001591 is 1951004302501.
It is a weak prime.
It is an emirp because it is prime and its reverse (1951004302501) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1052034001591 - 21 = 1052034001589 is a prime.
It is a super-2 number, since 2×10520340015912 (a number of 25 digits) contains 22 as substring.
Together with 1052034001589, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1052034001597) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 526017000795 + 526017000796.
It is an arithmetic number, because the mean of its divisors is an integer number (526017000796).
Almost surely, 21052034001591 is an apocalyptic number.
1052034001591 is a deficient number, since it is larger than the sum of its proper divisors (1).
1052034001591 is an equidigital number, since it uses as much as digits as its factorization.
1052034001591 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5400, while the sum is 31.
The spelling of 1052034001591 in words is "one trillion, fifty-two billion, thirty-four million, one thousand, five hundred ninety-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.080 sec. • engine limits •