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105254504438 = 253992967023
BaseRepresentation
bin110001000000110101…
…0000100011111110110
3101001200100220211021012
41202001222010133312
53211030123120223
6120204145152222
710414206345266
oct1420152043766
9331610824235
10105254504438
1140702473056
121849562b672
139c052ca075
145146c517a6
152b106b4c78
hex1881a847f6

105254504438 has 8 divisors (see below), whose sum is σ = 160860657888. Its totient is φ = 51634285144.

The previous prime is 105254504393. The next prime is 105254504441. The reversal of 105254504438 is 834405452501.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×1052545044382 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 105254504395 and 105254504404.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 496483406 + ... + 496483617.

It is an arithmetic number, because the mean of its divisors is an integer number (20107582236).

Almost surely, 2105254504438 is an apocalyptic number.

105254504438 is a deficient number, since it is larger than the sum of its proper divisors (55606153450).

105254504438 is an equidigital number, since it uses as much as digits as its factorization.

105254504438 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 992967078.

The product of its (nonzero) digits is 384000, while the sum is 41.

Adding to 105254504438 its reverse (834405452501), we get a palindrome (939659956939).

The spelling of 105254504438 in words is "one hundred five billion, two hundred fifty-four million, five hundred four thousand, four hundred thirty-eight".

Divisors: 1 2 53 106 992967023 1985934046 52627252219 105254504438