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1053136125103 = 2602940460107
BaseRepresentation
bin11110101001100111100…
…11011111110010101111
310201200022212102020222111
433110303303133302233
5114223310322000403
62123445402024451
7136041460235446
oct17246363376257
93650285366874
101053136125103
113766a5984177
121501311a8127
13784059a149a
1438d87495d5d
151c5db5dd56d
hexf533cdfcaf

1053136125103 has 4 divisors (see below), whose sum is σ = 1053176611240. Its totient is φ = 1053095638968.

The previous prime is 1053136125091. The next prime is 1053136125187. The reversal of 1053136125103 is 3015216313501.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1053136125103 - 213 = 1053136116911 is a prime.

It is a super-2 number, since 2×10531361251032 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1053136125193) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20204025 + ... + 20256082.

It is an arithmetic number, because the mean of its divisors is an integer number (263294152810).

Almost surely, 21053136125103 is an apocalyptic number.

1053136125103 is a deficient number, since it is larger than the sum of its proper divisors (40486137).

1053136125103 is an equidigital number, since it uses as much as digits as its factorization.

1053136125103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 40486136.

The product of its (nonzero) digits is 8100, while the sum is 31.

The spelling of 1053136125103 in words is "one trillion, fifty-three billion, one hundred thirty-six million, one hundred twenty-five thousand, one hundred three".

Divisors: 1 26029 40460107 1053136125103