Base | Representation |
---|---|
bin | 10011100111011100… |
… | …01110101010010111 |
3 | 1000011221202020022012 |
4 | 21303232032222113 |
5 | 133032021324421 |
6 | 4501005054435 |
7 | 521656463423 |
oct | 116356165227 |
9 | 30157666265 |
10 | 10531433111 |
11 | 45147a0631 |
12 | 205ab5741b |
13 | cbab29934 |
14 | 71c97bb83 |
15 | 41988495b |
hex | 273b8ea97 |
10531433111 has 8 divisors (see below), whose sum is σ = 10679885424. Its totient is φ = 10383094080.
The previous prime is 10531433009. The next prime is 10531433141. The reversal of 10531433111 is 11133413501.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 10531433111 - 222 = 10527238807 is a prime.
It is a super-2 number, since 2×105314331112 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (10531433141) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 168476 + ... + 222366.
It is an arithmetic number, because the mean of its divisors is an integer number (1334985678).
Almost surely, 210531433111 is an apocalyptic number.
10531433111 is a deficient number, since it is larger than the sum of its proper divisors (148452313).
10531433111 is an equidigital number, since it uses as much as digits as its factorization.
10531433111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 56641.
The product of its (nonzero) digits is 540, while the sum is 23.
Adding to 10531433111 its reverse (11133413501), we get a palindrome (21664846612).
The spelling of 10531433111 in words is "ten billion, five hundred thirty-one million, four hundred thirty-three thousand, one hundred eleven".
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