1053220433 has 4 divisors (see below), whose sum is σ = 1054939188. Its totient is φ = 1051501680.

The previous prime is 1053220411. The next prime is 1053220447. The reversal of 1053220433 is 3340223501.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3340223501 = 10559 ⋅316339.

It can be written as a sum of positive squares in 2 ways, for example, as 100140049 + 953080384 = 10007^2 + 30872^2 .

It is a cyclic number.

It is not a de Polignac number, because 1053220433 - 2¹² = 1053216337 is a prime.

It is a super-2 number, since 2×1053220433² = 2218546560977414978, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1053220399 and 1053220408.

It is not an unprimeable number, because it can be changed into a prime (1053720433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 858458 + ... + 859683.

It is an arithmetic number, because the mean of its divisors is an integer number (263734797).

Almost surely, 2^1053220433 is an apocalyptic number.

It is an amenable number.

1053220433 is a deficient number, since it is larger than the sum of its proper divisors (1718755).

1053220433 is an equidigital number, since it uses as much as digits as its factorization.

1053220433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1718754.

The product of its (nonzero) digits is 2160, while the sum is 23.

The square root of 1053220433 is about 32453.3578077832. The cubic root of 1053220433 is about 1017.4344189209.

Adding to 1053220433 its reverse (3340223501), we get a palindrome (4393443934).

The spelling of 1053220433 in words is "one billion, fifty-three million, two hundred twenty thousand, four hundred thirty-three".