1053221480711 has 2 divisors, whose sum is σ = 1053221480712. Its totient is φ = 1053221480710.

The previous prime is 1053221480653. The next prime is 1053221480713. The reversal of 1053221480711 is 1170841223501.

1053221480711 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (1170841223501) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1053221480711 - 2¹⁴ = 1053221464327 is a prime.

It is a super-2 number, since 2×1053221480711² (a number of 25 digits) contains 22 as substring.

Together with 1053221480713, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1053221480713) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 526610740355 + 526610740356.

It is an arithmetic number, because the mean of its divisors is an integer number (526610740356).

Almost surely, 2^{1053221480711} is an apocalyptic number.

1053221480711 is a deficient number, since it is larger than the sum of its proper divisors (1).

1053221480711 is an equidigital number, since it uses as much as digits as its factorization.

1053221480711 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13440, while the sum is 35.

The spelling of 1053221480711 in words is "one trillion, fifty-three billion, two hundred twenty-one million, four hundred eighty thousand, seven hundred eleven".