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1053334112151 = 3351111370717
BaseRepresentation
bin11110101001111111001…
…10110000011110010111
310201200211122222001011010
433110333212300132113
5114224212013042101
62123521153343303
7136046413140246
oct17247746603627
93650748861133
101053334112151
11376797711832
12150187567b33
1378437a02499
1438da58b295d
151c5edb9b2d6
hexf53f9b0797

1053334112151 has 4 divisors (see below), whose sum is σ = 1404445482872. Its totient is φ = 702222741432.

The previous prime is 1053334112137. The next prime is 1053334112179. The reversal of 1053334112151 is 1512114333501.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 1053334112151 - 26 = 1053334112087 is a prime.

It is a super-2 number, since 2×10533341121512 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1053334112651) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 175555685356 + ... + 175555685361.

It is an arithmetic number, because the mean of its divisors is an integer number (351111370718).

Almost surely, 21053334112151 is an apocalyptic number.

1053334112151 is a deficient number, since it is larger than the sum of its proper divisors (351111370721).

1053334112151 is an equidigital number, since it uses as much as digits as its factorization.

1053334112151 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 351111370720.

The product of its (nonzero) digits is 5400, while the sum is 30.

Adding to 1053334112151 its reverse (1512114333501), we get a palindrome (2565448445652).

The spelling of 1053334112151 in words is "one trillion, fifty-three billion, three hundred thirty-four million, one hundred twelve thousand, one hundred fifty-one".

Divisors: 1 3 351111370717 1053334112151