1053412015441 has 4 divisors (see below), whose sum is σ = 1115377428132. Its totient is φ = 991446602752.

The previous prime is 1053412015433. The next prime is 1053412015471. The reversal of 1053412015441 is 1445102143501.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 752866847041 + 300545168400 = 867679^2 + 548220^2 .

It is a cyclic number.

It is not a de Polignac number, because 1053412015441 - 2³ = 1053412015433 is a prime.

It is a super-3 number, since 3×1053412015441³ (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1053412015471) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30982706320 + ... + 30982706353.

It is an arithmetic number, because the mean of its divisors is an integer number (278844357033).

Almost surely, 2^{1053412015441} is an apocalyptic number.

It is an amenable number.

1053412015441 is a deficient number, since it is larger than the sum of its proper divisors (61965412691).

1053412015441 is an equidigital number, since it uses as much as digits as its factorization.

1053412015441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 61965412690.

The product of its (nonzero) digits is 9600, while the sum is 31.

Adding to 1053412015441 its reverse (1445102143501), we get a palindrome (2498514158942).

The spelling of 1053412015441 in words is "one trillion, fifty-three billion, four hundred twelve million, fifteen thousand, four hundred forty-one".