Base | Representation |
---|---|
bin | 110001000011110011… |
… | …0011001000000101111 |
3 | 101001221022112001020022 |
4 | 1202013212121000233 |
5 | 3211231134000213 |
6 | 120222110112355 |
7 | 10416526644215 |
oct | 1420746310057 |
9 | 331838461208 |
10 | 105354203183 |
11 | 40753779209 |
12 | 18502aab6bb |
13 | 9c1cb666c8 |
14 | 51561a4cb5 |
15 | 2b1930a308 |
hex | 188799902f |
105354203183 has 2 divisors, whose sum is σ = 105354203184. Its totient is φ = 105354203182.
The previous prime is 105354203137. The next prime is 105354203203. The reversal of 105354203183 is 381302453501.
It is a strong prime.
It is an emirp because it is prime and its reverse (381302453501) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 105354203183 - 210 = 105354202159 is a prime.
It is a super-2 number, since 2×1053542031832 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (105354202183) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52677101591 + 52677101592.
It is an arithmetic number, because the mean of its divisors is an integer number (52677101592).
Almost surely, 2105354203183 is an apocalyptic number.
105354203183 is a deficient number, since it is larger than the sum of its proper divisors (1).
105354203183 is an equidigital number, since it uses as much as digits as its factorization.
105354203183 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 43200, while the sum is 35.
Adding to 105354203183 its reverse (381302453501), we get a palindrome (486656656684).
The spelling of 105354203183 in words is "one hundred five billion, three hundred fifty-four million, two hundred three thousand, one hundred eighty-three".
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