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1053587147 is a prime number
BaseRepresentation
bin111110110011000…
…111011011001011
32201102111202212012
4332303013123023
54124204242042
6252314010135
735052225434
oct7663073313
92642452765
101053587147
114a07a4688
12254a1694b
1313a380262
149dcda48b
1562768e82
hex3ecc76cb

1053587147 has 2 divisors, whose sum is σ = 1053587148. Its totient is φ = 1053587146.

The previous prime is 1053587141. The next prime is 1053587149. The reversal of 1053587147 is 7417853501.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1053587147 - 26 = 1053587083 is a prime.

It is a super-2 number, since 2×10535871472 = 2220091752647199218, which contains 22 as substring.

Together with 1053587149, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1053587141) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 526793573 + 526793574.

It is an arithmetic number, because the mean of its divisors is an integer number (526793574).

Almost surely, 21053587147 is an apocalyptic number.

1053587147 is a deficient number, since it is larger than the sum of its proper divisors (1).

1053587147 is an equidigital number, since it uses as much as digits as its factorization.

1053587147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 117600, while the sum is 41.

The square root of 1053587147 is about 32459.0071782857. The cubic root of 1053587147 is about 1017.5524898517.

The spelling of 1053587147 in words is "one billion, fifty-three million, five hundred eighty-seven thousand, one hundred forty-seven".