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10540044335 = 514831421449
BaseRepresentation
bin10011101000011110…
…00101000000101111
31000012112221201200102
421310033011000233
5133041222404320
64501513421315
7522122620142
oct116417050057
930175851612
1010540044335
114519642347
122061a0a83b
13cbc853332
1471db80059
1541a4d6175
hex2743c502f

10540044335 has 8 divisors (see below), whose sum is σ = 12656590800. Its totient is φ = 8426343744.

The previous prime is 10540044329. The next prime is 10540044367. The reversal of 10540044335 is 53344004501.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 10540044335 - 232 = 6245077039 is a prime.

It is a super-2 number, since 2×105400443352 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10540044298 and 10540044307.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 703310 + ... + 718139.

It is an arithmetic number, because the mean of its divisors is an integer number (1582073850).

Almost surely, 210540044335 is an apocalyptic number.

10540044335 is a deficient number, since it is larger than the sum of its proper divisors (2116546465).

10540044335 is a wasteful number, since it uses less digits than its factorization.

10540044335 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1422937.

The product of its (nonzero) digits is 14400, while the sum is 29.

Adding to 10540044335 its reverse (53344004501), we get a palindrome (63884048836).

The spelling of 10540044335 in words is "ten billion, five hundred forty million, forty-four thousand, three hundred thirty-five".

Divisors: 1 5 1483 7415 1421449 7107245 2108008867 10540044335