Base | Representation |
---|---|
bin | 11110101011010010011… |
… | …00111111100110111111 |
3 | 10201202122022011111022201 |
4 | 33111221030333212333 |
5 | 114232124143021341 |
6 | 2124114323452331 |
7 | 136102616121061 |
oct | 17255114774677 |
9 | 3652568144281 |
10 | 1054032001471 |
11 | 37701564a369 |
12 | 1503412270a7 |
13 | 78519482c47 |
14 | 3903045b731 |
15 | 1c6400a3331 |
hex | f56933f9bf |
1054032001471 has 2 divisors, whose sum is σ = 1054032001472. Its totient is φ = 1054032001470.
The previous prime is 1054032001423. The next prime is 1054032001499. The reversal of 1054032001471 is 1741002304501.
It is an a-pointer prime, because the next prime (1054032001499) can be obtained adding 1054032001471 to its sum of digits (28).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1054032001471 - 213 = 1054031993279 is a prime.
It is a super-3 number, since 3×10540320014713 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1054032001411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 527016000735 + 527016000736.
It is an arithmetic number, because the mean of its divisors is an integer number (527016000736).
Almost surely, 21054032001471 is an apocalyptic number.
1054032001471 is a deficient number, since it is larger than the sum of its proper divisors (1).
1054032001471 is an equidigital number, since it uses as much as digits as its factorization.
1054032001471 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3360, while the sum is 28.
Adding to 1054032001471 its reverse (1741002304501), we get a palindrome (2795034305972).
The spelling of 1054032001471 in words is "one trillion, fifty-four billion, thirty-two million, one thousand, four hundred seventy-one".
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