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105434121241 is a prime number
BaseRepresentation
bin110001000110001011…
…1010000010000011001
3101002010212220022012101
41202030113100100121
53211412113334431
6120234043043401
710421520146401
oct1421427202031
9332125808171
10105434121241
11407948a3899
1218525810561
139c335986b7
145162a49801
152b21344961
hex188c5d0419

105434121241 has 2 divisors, whose sum is σ = 105434121242. Its totient is φ = 105434121240.

The previous prime is 105434121239. The next prime is 105434121257. The reversal of 105434121241 is 142121434501.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 99146265625 + 6287855616 = 314875^2 + 79296^2 .

It is a cyclic number.

It is not a de Polignac number, because 105434121241 - 21 = 105434121239 is a prime.

It is a super-2 number, since 2×1054341212412 (a number of 23 digits) contains 22 as substring.

Together with 105434121239, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (105434191241) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52717060620 + 52717060621.

It is an arithmetic number, because the mean of its divisors is an integer number (52717060621).

Almost surely, 2105434121241 is an apocalyptic number.

It is an amenable number.

105434121241 is a deficient number, since it is larger than the sum of its proper divisors (1).

105434121241 is an equidigital number, since it uses as much as digits as its factorization.

105434121241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3840, while the sum is 28.

Adding to 105434121241 its reverse (142121434501), we get a palindrome (247555555742).

The spelling of 105434121241 in words is "one hundred five billion, four hundred thirty-four million, one hundred twenty-one thousand, two hundred forty-one".