105441504013 has 2 divisors, whose sum is σ = 105441504014. Its totient is φ = 105441504012.

The previous prime is 105441504011. The next prime is 105441504029. The reversal of 105441504013 is 310405144501.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 71650976329 + 33790527684 = 267677^2 + 183822^2 .

It is an emirp because it is prime and its reverse (310405144501) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 105441504013 - 2¹ = 105441504011 is a prime.

It is a super-3 number, since 3×105441504013³ (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

Together with 105441504011, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (105441504011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52720752006 + 52720752007.

It is an arithmetic number, because the mean of its divisors is an integer number (52720752007).

Almost surely, 2^105441504013 is an apocalyptic number.

It is an amenable number.

105441504013 is a deficient number, since it is larger than the sum of its proper divisors (1).

105441504013 is an equidigital number, since it uses as much as digits as its factorization.

105441504013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4800, while the sum is 28.

Adding to 105441504013 its reverse (310405144501), we get a palindrome (415846648514).

The spelling of 105441504013 in words is "one hundred five billion, four hundred forty-one million, five hundred four thousand, thirteen".