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10545044303 is a prime number
BaseRepresentation
bin10011101001000100…
…01001101101001111
31000012220100202100102
421310202021231033
5133044012404203
64502212521315
7522213253253
oct116442115517
930186322312
1010545044303
114521447952
12206362023b
13cc08b40b1
147206c2263
1541ab72888
hex274889b4f

10545044303 has 2 divisors, whose sum is σ = 10545044304. Its totient is φ = 10545044302.

The previous prime is 10545044297. The next prime is 10545044371. The reversal of 10545044303 is 30344054501.

10545044303 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 10545044303 - 28 = 10545044047 is a prime.

It is a super-2 number, since 2×105450443032 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10545044383) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5272522151 + 5272522152.

It is an arithmetic number, because the mean of its divisors is an integer number (5272522152).

Almost surely, 210545044303 is an apocalyptic number.

10545044303 is a deficient number, since it is larger than the sum of its proper divisors (1).

10545044303 is an equidigital number, since it uses as much as digits as its factorization.

10545044303 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14400, while the sum is 29.

Adding to 10545044303 its reverse (30344054501), we get a palindrome (40889098804).

The spelling of 10545044303 in words is "ten billion, five hundred forty-five million, forty-four thousand, three hundred three".