Base | Representation |
---|---|
bin | 110001001001101001… |
… | …1001101001000111111 |
3 | 101002102222212222102011 |
4 | 1202103103031020333 |
5 | 3212131412003130 |
6 | 120253401312051 |
7 | 10424432310313 |
oct | 1422323151077 |
9 | 332388788364 |
10 | 105550500415 |
11 | 40844562228 |
12 | 18558795627 |
13 | 9c51725509 |
14 | 51742a1b43 |
15 | 2b2b68252a |
hex | 18934cd23f |
105550500415 has 4 divisors (see below), whose sum is σ = 126660600504. Its totient is φ = 84440400328.
The previous prime is 105550500403. The next prime is 105550500421. The reversal of 105550500415 is 514005055501.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 105550500415 - 211 = 105550498367 is a prime.
It is a super-2 number, since 2×1055505004152 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10555050037 + ... + 10555050046.
It is an arithmetic number, because the mean of its divisors is an integer number (31665150126).
Almost surely, 2105550500415 is an apocalyptic number.
105550500415 is a deficient number, since it is larger than the sum of its proper divisors (21110100089).
105550500415 is an equidigital number, since it uses as much as digits as its factorization.
105550500415 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 21110100088.
The product of its (nonzero) digits is 12500, while the sum is 31.
Adding to 105550500415 its reverse (514005055501), we get a palindrome (619555555916).
The spelling of 105550500415 in words is "one hundred five billion, five hundred fifty million, five hundred thousand, four hundred fifteen".
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