Base | Representation |
---|---|
bin | 11110101110011110100… |
… | …00001011000111101011 |
3 | 10201221001121210200011211 |
4 | 33113033100023013223 |
5 | 114244130443023313 |
6 | 2125000244133551 |
7 | 136163215610224 |
oct | 17271720130753 |
9 | 3657047720154 |
10 | 1055744111083 |
11 | 377814033692 |
12 | 15073a6972b7 |
13 | 787300ac35c |
14 | 391539b624b |
15 | 1c6e0549e3d |
hex | f5cf40b1eb |
1055744111083 has 2 divisors, whose sum is σ = 1055744111084. Its totient is φ = 1055744111082.
The previous prime is 1055744111027. The next prime is 1055744111099. The reversal of 1055744111083 is 3801114475501.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1055744111083 is a prime.
It is a super-3 number, since 3×10557441110833 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (1055744111003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 527872055541 + 527872055542.
It is an arithmetic number, because the mean of its divisors is an integer number (527872055542).
Almost surely, 21055744111083 is an apocalyptic number.
1055744111083 is a deficient number, since it is larger than the sum of its proper divisors (1).
1055744111083 is an equidigital number, since it uses as much as digits as its factorization.
1055744111083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 67200, while the sum is 40.
Adding to 1055744111083 its reverse (3801114475501), we get a palindrome (4856858586584).
The spelling of 1055744111083 in words is "one trillion, fifty-five billion, seven hundred forty-four million, one hundred eleven thousand, eighty-three".
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