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10642633042981 is a prime number
BaseRepresentation
bin1001101011011110111001…
…0111001010110000100101
31101200102111101200021202111
42122313232113022300211
52343332103024333411
634345054053241021
72145622240155262
oct232675627126045
941612441607674
1010642633042981
113433573999835
12123a744333171
135c279950a284
1428b16b544269
15136c8ca03721
hex9adee5cac25

10642633042981 has 2 divisors, whose sum is σ = 10642633042982. Its totient is φ = 10642633042980.

The previous prime is 10642633042969. The next prime is 10642633043117. The reversal of 10642633042981 is 18924033624601.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10064058312100 + 578574730881 = 3172390^2 + 760641^2 .

It is a cyclic number.

It is not a de Polignac number, because 10642633042981 - 25 = 10642633042949 is a prime.

It is a super-3 number, since 3×106426330429813 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10642633042081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5321316521490 + 5321316521491.

It is an arithmetic number, because the mean of its divisors is an integer number (5321316521491).

Almost surely, 210642633042981 is an apocalyptic number.

It is an amenable number.

10642633042981 is a deficient number, since it is larger than the sum of its proper divisors (1).

10642633042981 is an equidigital number, since it uses as much as digits as its factorization.

10642633042981 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1492992, while the sum is 49.

The spelling of 10642633042981 in words is "ten trillion, six hundred forty-two billion, six hundred thirty-three million, forty-two thousand, nine hundred eighty-one".