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10642633043117 is a prime number
BaseRepresentation
bin1001101011011110111001…
…0111001010110010101101
31101200102111101200021221112
42122313232113022302231
52343332103024334432
634345054053241405
72145622240155545
oct232675627126255
941612441607845
1010642633043117
113433573999949
12123a744333265
135c279950a35a
1428b16b544325
15136c8ca037b2
hex9adee5cacad

10642633043117 has 2 divisors, whose sum is σ = 10642633043118. Its totient is φ = 10642633043116.

The previous prime is 10642633042981. The next prime is 10642633043131. The reversal of 10642633043117 is 71134033624601.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9432674842756 + 1209958200361 = 3071266^2 + 1099981^2 .

It is a cyclic number.

It is not a de Polignac number, because 10642633043117 - 212 = 10642633039021 is a prime.

It is a super-3 number, since 3×106426330431173 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10642633043197) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5321316521558 + 5321316521559.

It is an arithmetic number, because the mean of its divisors is an integer number (5321316521559).

Almost surely, 210642633043117 is an apocalyptic number.

It is an amenable number.

10642633043117 is a deficient number, since it is larger than the sum of its proper divisors (1).

10642633043117 is an equidigital number, since it uses as much as digits as its factorization.

10642633043117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 217728, while the sum is 41.

Adding to 10642633043117 its reverse (71134033624601), we get a palindrome (81776666667718).

The spelling of 10642633043117 in words is "ten trillion, six hundred forty-two billion, six hundred thirty-three million, forty-three thousand, one hundred seventeen".