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1064952128593 is a prime number
BaseRepresentation
bin11110111111101000001…
…01111110010001010001
310202210211100022102120101
433133310011332101101
5114422010221103333
62133122100012401
7136640335510303
oct17376405762121
93683740272511
101064952128593
11380709793511
1215248a391101
1379569993022
1439788899973
151ca7db1667d
hexf7f417e451

1064952128593 has 2 divisors, whose sum is σ = 1064952128594. Its totient is φ = 1064952128592.

The previous prime is 1064952128587. The next prime is 1064952128599. The reversal of 1064952128593 is 3958212594601.

It is a balanced prime because it is at equal distance from previous prime (1064952128587) and next prime (1064952128599).

It can be written as a sum of positive squares in only one way, i.e., 1053439482384 + 11512646209 = 1026372^2 + 107297^2 .

It is a cyclic number.

It is not a de Polignac number, because 1064952128593 - 221 = 1064950031441 is a prime.

It is a super-2 number, since 2×10649521285932 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1064952128599) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 532476064296 + 532476064297.

It is an arithmetic number, because the mean of its divisors is an integer number (532476064297).

Almost surely, 21064952128593 is an apocalyptic number.

It is an amenable number.

1064952128593 is a deficient number, since it is larger than the sum of its proper divisors (1).

1064952128593 is an equidigital number, since it uses as much as digits as its factorization.

1064952128593 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4665600, while the sum is 55.

The spelling of 1064952128593 in words is "one trillion, sixty-four billion, nine hundred fifty-two million, one hundred twenty-eight thousand, five hundred ninety-three".