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109398825433 = 2343110615597
BaseRepresentation
bin110010111100010101…
…1011001100111011001
3101110101012012010220101
41211320223121213121
53243022044403213
6122131312255401
710622001446632
oct1457053314731
9343335163811
10109398825433
114243986a827
1219251541561
13a415aac801
14541b412889
152ca4446bdd
hex1978ad99d9

109398825433 has 8 divisors (see below), whose sum is σ = 116810071488. Its totient is φ = 102208810704.

The previous prime is 109398825421. The next prime is 109398825443. The reversal of 109398825433 is 334528893901.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-109398825433 is a prime.

It is a super-2 number, since 2×1093988254332 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (109398825413) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 55306810 + ... + 55308787.

It is an arithmetic number, because the mean of its divisors is an integer number (14601258936).

Almost surely, 2109398825433 is an apocalyptic number.

It is an amenable number.

109398825433 is a deficient number, since it is larger than the sum of its proper divisors (7411246055).

109398825433 is a wasteful number, since it uses less digits than its factorization.

109398825433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 110615663.

The product of its (nonzero) digits is 5598720, while the sum is 55.

The spelling of 109398825433 in words is "one hundred nine billion, three hundred ninety-eight million, eight hundred twenty-five thousand, four hundred thirty-three".

Divisors: 1 23 43 989 110615597 2544158731 4756470671 109398825433