Base | Representation |
---|---|
bin | 110011001100011101… |
… | …1000110011100100111 |
3 | 101111202220011010010220 |
4 | 1212120323012130213 |
5 | 3300124042442020 |
6 | 122301115415423 |
7 | 10641260661426 |
oct | 1463073063447 |
9 | 344686133126 |
10 | 109939812135 |
11 | 4269718107a |
12 | 19382754573 |
13 | a4a0bb559a |
14 | 546d1d72bd |
15 | 2cd6ba9240 |
hex | 1998ec6727 |
109939812135 has 8 divisors (see below), whose sum is σ = 175903699440. Its totient is φ = 58634566464.
The previous prime is 109939812127. The next prime is 109939812139. The reversal of 109939812135 is 531218939901.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 109939812135 - 23 = 109939812127 is a prime.
It is a Smith number, since the sum of its digits (51) coincides with the sum of the digits of its prime factors. Since it is squarefree, it is also a hoax number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (109939812139) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3664660390 + ... + 3664660419.
It is an arithmetic number, because the mean of its divisors is an integer number (21987962430).
Almost surely, 2109939812135 is an apocalyptic number.
109939812135 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
109939812135 is a deficient number, since it is larger than the sum of its proper divisors (65963887305).
109939812135 is an equidigital number, since it uses as much as digits as its factorization.
109939812135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7329320817.
The product of its (nonzero) digits is 524880, while the sum is 51.
The spelling of 109939812135 in words is "one hundred nine billion, nine hundred thirty-nine million, eight hundred twelve thousand, one hundred thirty-five".
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