11000001001117 has 2 divisors, whose sum is σ = 11000001001118. Its totient is φ = 11000001001116.

The previous prime is 11000001001111. The next prime is 11000001001141. The reversal of 11000001001117 is 71110010000011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8784946251481 + 2215054749636 = 2963941^2 + 1488306^2 .

It is a cyclic number.

It is not a de Polignac number, because 11000001001117 - 2¹⁵ = 11000000968349 is a prime.

It is a super-3 number, since 3×11000001001117³ (a number of 40 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11000001001097 and 11000001001106.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11000001001111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500000500558 + 5500000500559.

It is an arithmetic number, because the mean of its divisors is an integer number (5500000500559).

Almost surely, 2^{11000001001117} is an apocalyptic number.

It is an amenable number.

11000001001117 is a deficient number, since it is larger than the sum of its proper divisors (1).

11000001001117 is an equidigital number, since it uses as much as digits as its factorization.

11000001001117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7, while the sum is 13.

Adding to 11000001001117 its reverse (71110010000011), we get a palindrome (82110011001128).

The spelling of 11000001001117 in words is "eleven trillion, one million, one thousand, one hundred seventeen".