1100001000113 has 2 divisors, whose sum is σ = 1100001000114. Its totient is φ = 1100001000112.

The previous prime is 1100001000031. The next prime is 1100001000149. The reversal of 1100001000113 is 3110001000011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 743851051024 + 356149949089 = 862468^2 + 596783^2 .

It is a cyclic number.

It is not a de Polignac number, because 1100001000113 - 2²⁰ = 1099999951537 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 1100001000113.

It is not a weakly prime, because it can be changed into another prime (1100001000173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550000500056 + 550000500057.

It is an arithmetic number, because the mean of its divisors is an integer number (550000500057).

Almost surely, 2^{1100001000113} is an apocalyptic number.

It is an amenable number.

1100001000113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100001000113 is an equidigital number, since it uses as much as digits as its factorization.

1100001000113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3, while the sum is 8.

Adding to 1100001000113 its reverse (3110001000011), we get a palindrome (4210002000124).

The spelling of 1100001000113 in words is "one trillion, one hundred billion, one million, one hundred thirteen", and thus it is an aban number.