11000011101113 has 2 divisors, whose sum is σ = 11000011101114. Its totient is φ = 11000011101112.

The previous prime is 11000011101097. The next prime is 11000011101137. The reversal of 11000011101113 is 31110111000011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 5617833818809 + 5382177282304 = 2370197^2 + 2319952^2 .

It is an emirp because it is prime and its reverse (31110111000011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11000011101113 - 2⁴ = 11000011101097 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11000011101094 and 11000011101103.

It is not a weakly prime, because it can be changed into another prime (11000011101713) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500005550556 + 5500005550557.

It is an arithmetic number, because the mean of its divisors is an integer number (5500005550557).

Almost surely, 2^{11000011101113} is an apocalyptic number.

It is an amenable number.

11000011101113 is a deficient number, since it is larger than the sum of its proper divisors (1).

11000011101113 is an equidigital number, since it uses as much as digits as its factorization.

11000011101113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3, while the sum is 11.

Adding to 11000011101113 its reverse (31110111000011), we get a palindrome (42110122101124).

The spelling of 11000011101113 in words is "eleven trillion, eleven million, one hundred one thousand, one hundred thirteen".