Base | Representation |
---|---|
bin | 10000000000011101001… |
… | …011010001011101000101 |
3 | 10220011021222011202222122 |
4 | 100000131023101131011 |
5 | 121010300241401432 |
6 | 2201200013335325 |
7 | 142321024160012 |
oct | 20003513213505 |
9 | 3804258152878 |
10 | 1100001122117 |
11 | 394564a58067 |
12 | 159230197545 |
13 | 7c9640abc51 |
14 | 3b3516ba709 |
15 | 1d930b23612 |
hex | 1001d2d1745 |
1100001122117 has 2 divisors, whose sum is σ = 1100001122118. Its totient is φ = 1100001122116.
The previous prime is 1100001122107. The next prime is 1100001122153. The reversal of 1100001122117 is 7112211000011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 802375228516 + 297625893601 = 895754^2 + 545551^2 .
It is a cyclic number.
It is not a de Polignac number, because 1100001122117 - 214 = 1100001105733 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1100001122095 and 1100001122104.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1100001122107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550000561058 + 550000561059.
It is an arithmetic number, because the mean of its divisors is an integer number (550000561059).
Almost surely, 21100001122117 is an apocalyptic number.
It is an amenable number.
1100001122117 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100001122117 is an equidigital number, since it uses as much as digits as its factorization.
1100001122117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 28, while the sum is 17.
Adding to 1100001122117 its reverse (7112211000011), we get a palindrome (8212212122128).
The spelling of 1100001122117 in words is "one trillion, one hundred billion, one million, one hundred twenty-two thousand, one hundred seventeen".
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