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110000113133 = 472340427939
BaseRepresentation
bin110011001110010000…
…1001000010111101101
3101111221002121201120012
41212130201020113231
53300240012110013
6122311112103005
710642622351201
oct1463441102755
9344832551505
10110000113133
1142718218109
121939a994a65
13a4b0539551
145477212b01
152cdc11b1a8
hex199c8485ed

110000113133 has 4 divisors (see below), whose sum is σ = 112340541120. Its totient is φ = 107659685148.

The previous prime is 110000113127. The next prime is 110000113163. The reversal of 110000113133 is 331311000011.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 110000113133 - 28 = 110000112877 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (110000113163) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1170213923 + ... + 1170214016.

It is an arithmetic number, because the mean of its divisors is an integer number (28085135280).

Almost surely, 2110000113133 is an apocalyptic number.

It is an amenable number.

110000113133 is a deficient number, since it is larger than the sum of its proper divisors (2340427987).

110000113133 is an equidigital number, since it uses as much as digits as its factorization.

110000113133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2340427986.

The product of its (nonzero) digits is 27, while the sum is 14.

Adding to 110000113133 its reverse (331311000011), we get a palindrome (441311113144).

The spelling of 110000113133 in words is "one hundred ten billion, one hundred thirteen thousand, one hundred thirty-three".

Divisors: 1 47 2340427939 110000113133