Base | Representation |
---|---|
bin | 11001000000101101101100… |
… | …001010001000001011110011 |
3 | 112102110220210121022011112012 |
4 | 121000231230022020023303 |
5 | 103404220423313342042 |
6 | 1025541223202153135 |
7 | 32112153021553355 |
oct | 3100555412101363 |
9 | 472426717264465 |
10 | 110000222012147 |
11 | 3205a917698205 |
12 | 104069439527ab |
13 | 494bc902949ac |
14 | 1d240796130d5 |
15 | cab558e68e82 |
hex | 640b6c2882f3 |
110000222012147 has 2 divisors, whose sum is σ = 110000222012148. Its totient is φ = 110000222012146.
The previous prime is 110000222012071. The next prime is 110000222012179. The reversal of 110000222012147 is 741210222000011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 110000222012147 - 212 = 110000222008051 is a prime.
It is not a weakly prime, because it can be changed into another prime (110000222012347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55000111006073 + 55000111006074.
It is an arithmetic number, because the mean of its divisors is an integer number (55000111006074).
Almost surely, 2110000222012147 is an apocalyptic number.
110000222012147 is a deficient number, since it is larger than the sum of its proper divisors (1).
110000222012147 is an equidigital number, since it uses as much as digits as its factorization.
110000222012147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 448, while the sum is 23.
Adding to 110000222012147 its reverse (741210222000011), we get a palindrome (851210444012158).
The spelling of 110000222012147 in words is "one hundred ten trillion, two hundred twenty-two million, twelve thousand, one hundred forty-seven".
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