11000043413 has 2 divisors, whose sum is σ = 11000043414. Its totient is φ = 11000043412.

The previous prime is 11000043403. The next prime is 11000043433. The reversal of 11000043413 is 31434000011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10850763889 + 149279524 = 104167^2 + 12218^2 .

It is a cyclic number.

It is not a de Polignac number, because 11000043413 - 2²⁰ = 10998994837 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11000043391 and 11000043400.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11000043403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500021706 + 5500021707.

It is an arithmetic number, because the mean of its divisors is an integer number (5500021707).

Almost surely, 2^11000043413 is an apocalyptic number.

It is an amenable number.

11000043413 is a deficient number, since it is larger than the sum of its proper divisors (1).

11000043413 is an equidigital number, since it uses as much as digits as its factorization.

11000043413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 11000043413 its reverse (31434000011), we get a palindrome (42434043424).

The spelling of 11000043413 in words is "eleven billion, forty-three thousand, four hundred thirteen".