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110001000047 is a prime number
BaseRepresentation
bin110011001110010010…
…0100000111001101111
3101111221011021210011212
41212130210200321233
53300240224000142
6122311143105035
710642633034021
oct1463444407157
9344834253155
10110001000047
11427187734a4
121939b14217b
13a4b078a153
1454773a4011
152cdc243d82
hex199c920e6f

110001000047 has 2 divisors, whose sum is σ = 110001000048. Its totient is φ = 110001000046.

The previous prime is 110001000019. The next prime is 110001000073. The reversal of 110001000047 is 740000100011.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 110001000047 - 28 = 110000999791 is a prime.

It is a super-2 number, since 2×1100010000472 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 110000999995 and 110001000040.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110001000097) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55000500023 + 55000500024.

It is an arithmetic number, because the mean of its divisors is an integer number (55000500024).

Almost surely, 2110001000047 is an apocalyptic number.

110001000047 is a deficient number, since it is larger than the sum of its proper divisors (1).

110001000047 is an equidigital number, since it uses as much as digits as its factorization.

110001000047 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 28, while the sum is 14.

Adding to 110001000047 its reverse (740000100011), we get a palindrome (850001100058).

It can be divided in two parts, 11000100004 and 7, that added together give a palindrome (11000100011).

The spelling of 110001000047 in words is "one hundred ten billion, one million, forty-seven", and thus it is an aban number.