Base | Representation |
---|---|
bin | 110011001110010010… |
… | …0100000111010100111 |
3 | 101111221011021210020221 |
4 | 1212130210200322213 |
5 | 3300240224000403 |
6 | 122311143105211 |
7 | 10642633034131 |
oct | 1463444407247 |
9 | 344834253227 |
10 | 110001000103 |
11 | 42718773545 |
12 | 1939b142207 |
13 | a4b078a197 |
14 | 54773a4051 |
15 | 2cdc243dbd |
hex | 199c920ea7 |
110001000103 has 2 divisors, whose sum is σ = 110001000104. Its totient is φ = 110001000102.
The previous prime is 110001000097. The next prime is 110001000169. The reversal of 110001000103 is 301000100011.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-110001000103 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110001000803) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55000500051 + 55000500052.
It is an arithmetic number, because the mean of its divisors is an integer number (55000500052).
Almost surely, 2110001000103 is an apocalyptic number.
110001000103 is a deficient number, since it is larger than the sum of its proper divisors (1).
110001000103 is an equidigital number, since it uses as much as digits as its factorization.
110001000103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3, while the sum is 7.
Adding to 110001000103 its reverse (301000100011), we get a palindrome (411001100114).
The spelling of 110001000103 in words is "one hundred ten billion, one million, one hundred three", and thus it is an aban number.
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