Base | Representation |
---|---|
bin | 1010000000010010100100… |
… | …0011110001011110100111 |
3 | 1102221121011220000021201002 |
4 | 2200010221003301132213 |
5 | 2420211201111200012 |
6 | 35221213133023515 |
7 | 2213505510053144 |
oct | 240045103613647 |
9 | 42847156007632 |
10 | 11000100100007 |
11 | 3561130809597 |
12 | 1297a87324b9b |
13 | 61a3c70a1225 |
14 | 2a059c9913cb |
15 | 14121037d7c2 |
hex | a01290f17a7 |
11000100100007 has 2 divisors, whose sum is σ = 11000100100008. Its totient is φ = 11000100100006.
The previous prime is 11000100099991. The next prime is 11000100100061. The reversal of 11000100100007 is 70000100100011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11000100100007 - 24 = 11000100099991 is a prime.
It is a super-2 number, since 2×110001001000072 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11000100100097) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500050050003 + 5500050050004.
It is an arithmetic number, because the mean of its divisors is an integer number (5500050050004).
Almost surely, 211000100100007 is an apocalyptic number.
11000100100007 is a deficient number, since it is larger than the sum of its proper divisors (1).
11000100100007 is an equidigital number, since it uses as much as digits as its factorization.
11000100100007 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7, while the sum is 11.
Adding to 11000100100007 its reverse (70000100100011), we get a palindrome (81000200200018).
The spelling of 11000100100007 in words is "eleven trillion, one hundred million, one hundred thousand, seven".
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