Base | Representation |
---|---|
bin | 1010000000010010100100… |
… | …0111001101001110101111 |
3 | 1102221121011221201000102021 |
4 | 2200010221013031032233 |
5 | 2420211201324000421 |
6 | 35221213204211011 |
7 | 2213505520522306 |
oct | 240045107151657 |
9 | 42847157630367 |
10 | 11000101000111 |
11 | 3561131273883 |
12 | 1297a87699a67 |
13 | 61a3c7327b32 |
14 | 2a059cb4743d |
15 | 1412104aa341 |
hex | a01291cd3af |
11000101000111 has 2 divisors, whose sum is σ = 11000101000112. Its totient is φ = 11000101000110.
The previous prime is 11000101000043. The next prime is 11000101000129. The reversal of 11000101000111 is 11100010100011.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11000101000111 - 27 = 11000100999983 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11000101000094 and 11000101000103.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11000101000151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500050500055 + 5500050500056.
It is an arithmetic number, because the mean of its divisors is an integer number (5500050500056).
Almost surely, 211000101000111 is an apocalyptic number.
11000101000111 is a deficient number, since it is larger than the sum of its proper divisors (1).
11000101000111 is an equidigital number, since it uses as much as digits as its factorization.
11000101000111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1, while the sum is 7.
Adding to 11000101000111 its reverse (11100010100011), we get a palindrome (22100111100122).
The spelling of 11000101000111 in words is "eleven trillion, one hundred one million, one hundred eleven", and thus it is an aban number.
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