Base | Representation |
---|---|
bin | 1010000000010010100100… |
… | …0111001101011100010101 |
3 | 1102221121011221201001121111 |
4 | 2200010221013031130111 |
5 | 2420211201324012411 |
6 | 35221213204215021 |
7 | 2213505520524661 |
oct | 240045107153425 |
9 | 42847157631544 |
10 | 11000101000981 |
11 | 35611312744a4 |
12 | 1297a8769a471 |
13 | 61a3c7328351 |
14 | 2a059cb478a1 |
15 | 1412104aa721 |
hex | a01291cd715 |
11000101000981 has 2 divisors, whose sum is σ = 11000101000982. Its totient is φ = 11000101000980.
The previous prime is 11000101000879. The next prime is 11000101001033. The reversal of 11000101000981 is 18900010100011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8778835668100 + 2221265332881 = 2962910^2 + 1490391^2 .
It is a cyclic number.
It is not a de Polignac number, because 11000101000981 - 217 = 11000100869909 is a prime.
It is a super-2 number, since 2×110001010009812 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11000101000481) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500050500490 + 5500050500491.
It is an arithmetic number, because the mean of its divisors is an integer number (5500050500491).
Almost surely, 211000101000981 is an apocalyptic number.
It is an amenable number.
11000101000981 is a deficient number, since it is larger than the sum of its proper divisors (1).
11000101000981 is an equidigital number, since it uses as much as digits as its factorization.
11000101000981 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 22.
Adding to 11000101000981 its reverse (18900010100011), we get a palindrome (29900111100992).
The spelling of 11000101000981 in words is "eleven trillion, one hundred one million, nine hundred eighty-one", and thus it is an aban number.
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