Base | Representation |
---|---|
bin | 1010000000010010100100… |
… | …0111001111101001111111 |
3 | 1102221121011221201112001021 |
4 | 2200010221013033221333 |
5 | 2420211201324310142 |
6 | 35221213204325011 |
7 | 2213505520563262 |
oct | 240045107175177 |
9 | 42847157645037 |
10 | 11000101010047 |
11 | 3561131280296 |
12 | 1297a876a3767 |
13 | 61a3c732c506 |
14 | 2a059cb4acd9 |
15 | 1412104ad267 |
hex | a01291cfa7f |
11000101010047 has 2 divisors, whose sum is σ = 11000101010048. Its totient is φ = 11000101010046.
The previous prime is 11000101010039. The next prime is 11000101010071. The reversal of 11000101010047 is 74001010100011.
It is a happy number.
11000101010047 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11000101010047 - 23 = 11000101010039 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11000101010047.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11000101017047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500050505023 + 5500050505024.
It is an arithmetic number, because the mean of its divisors is an integer number (5500050505024).
Almost surely, 211000101010047 is an apocalyptic number.
11000101010047 is a deficient number, since it is larger than the sum of its proper divisors (1).
11000101010047 is an equidigital number, since it uses as much as digits as its factorization.
11000101010047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 28, while the sum is 16.
Adding to 11000101010047 its reverse (74001010100011), we get a palindrome (85001111110058).
The spelling of 11000101010047 in words is "eleven trillion, one hundred one million, ten thousand, forty-seven".
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