11000103433 has 4 divisors (see below), whose sum is σ = 12000112848. Its totient is φ = 10000094020.

The previous prime is 11000103431. The next prime is 11000103467. The reversal of 11000103433 is 33430100011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11000103433 - 2¹ = 11000103431 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11000103431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 500004691 + ... + 500004712.

It is an arithmetic number, because the mean of its divisors is an integer number (3000028212).

Almost surely, 2^11000103433 is an apocalyptic number.

It is an amenable number.

11000103433 is a deficient number, since it is larger than the sum of its proper divisors (1000009415).

11000103433 is a wasteful number, since it uses less digits than its factorization.

11000103433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1000009414.

The product of its (nonzero) digits is 108, while the sum is 16.

Adding to 11000103433 its reverse (33430100011), we get a palindrome (44430203444).

The spelling of 11000103433 in words is "eleven billion, one hundred three thousand, four hundred thirty-three".