Base | Representation |
---|---|
bin | 1010000000010010100110… |
… | …1101101111010010101111 |
3 | 1102221121012122201012101002 |
4 | 2200010221231233102233 |
5 | 2420211211420213403 |
6 | 35221214204510515 |
7 | 2213506002422255 |
oct | 240045155572257 |
9 | 42847178635332 |
10 | 11000111101103 |
11 | 3561136a42903 |
12 | 1297a8ab4b43b |
13 | 61a3c9453657 |
14 | 2a05a02165d5 |
15 | 141211303188 |
hex | a0129b6f4af |
11000111101103 has 2 divisors, whose sum is σ = 11000111101104. Its totient is φ = 11000111101102.
The previous prime is 11000111101027. The next prime is 11000111101153. The reversal of 11000111101103 is 30110111100011.
11000111101103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11000111101103 - 212 = 11000111097007 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11000111101153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500055550551 + 5500055550552.
It is an arithmetic number, because the mean of its divisors is an integer number (5500055550552).
Almost surely, 211000111101103 is an apocalyptic number.
11000111101103 is a deficient number, since it is larger than the sum of its proper divisors (1).
11000111101103 is an equidigital number, since it uses as much as digits as its factorization.
11000111101103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3, while the sum is 11.
Adding to 11000111101103 its reverse (30110111100011), we get a palindrome (41110222201114).
The spelling of 11000111101103 in words is "eleven trillion, one hundred eleven million, one hundred one thousand, one hundred three".
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