Base | Representation |
---|---|
bin | 100000110010000… |
… | …1101011001101101 |
3 | 2211122212100120111 |
4 | 1001210031121231 |
5 | 4223100323432 |
6 | 301053020021 |
7 | 36154640332 |
oct | 10144153155 |
9 | 2748770514 |
10 | 1100011117 |
11 | 514a226a7 |
12 | 268484611 |
13 | 146b85a6a |
14 | a6142989 |
15 | 66889347 |
hex | 4190d66d |
1100011117 has 2 divisors, whose sum is σ = 1100011118. Its totient is φ = 1100011116.
The previous prime is 1100011063. The next prime is 1100011127. The reversal of 1100011117 is 7111100011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 912704521 + 187306596 = 30211^2 + 13686^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1100011117 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1100011097 and 1100011106.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1100011127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550005558 + 550005559.
It is an arithmetic number, because the mean of its divisors is an integer number (550005559).
Almost surely, 21100011117 is an apocalyptic number.
It is an amenable number.
1100011117 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100011117 is an equidigital number, since it uses as much as digits as its factorization.
1100011117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7, while the sum is 13.
The square root of 1100011117 is about 33166.4154982114. The cubic root of 1100011117 is about 1032.2835929774.
Adding to 1100011117 its reverse (7111100011), we get a palindrome (8211111128).
The spelling of 1100011117 in words is "one billion, one hundred million, eleven thousand, one hundred seventeen".
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