110001233000013 has 4 divisors (see below), whose sum is σ = 146668310666688. Its totient is φ = 73334155333340.

The previous prime is 110001232999991. The next prime is 110001233000023. The reversal of 110001233000013 is 310000332100011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 110001233000013 - 2⁶ = 110001232999949 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 110001232999956 and 110001233000001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (110001233000023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18333538833333 + ... + 18333538833338.

It is an arithmetic number, because the mean of its divisors is an integer number (36667077666672).

Almost surely, 2^{110001233000013} is an apocalyptic number.

It is an amenable number.

110001233000013 is a deficient number, since it is larger than the sum of its proper divisors (36667077666675).

110001233000013 is an equidigital number, since it uses as much as digits as its factorization.

110001233000013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 36667077666674.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 110001233000013 its reverse (310000332100011), we get a palindrome (420001565100024).

The spelling of 110001233000013 in words is "one hundred ten trillion, one billion, two hundred thirty-three million, thirteen", and thus it is an aban number.