110001312314 has 4 divisors (see below), whose sum is σ = 165001968474. Its totient is φ = 55000656156.

The previous prime is 110001312313. The next prime is 110001312349. The reversal of 110001312314 is 413213100011.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 109908825625 + 92486689 = 331525^2 + 9617^2 .

It is a junction number, because it is equal to n+sod(n) for n = 110001312292 and 110001312301.

It is not an unprimeable number, because it can be changed into a prime (110001312313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27500328077 + ... + 27500328080.

Almost surely, 2^110001312314 is an apocalyptic number.

110001312314 is a deficient number, since it is larger than the sum of its proper divisors (55000656160).

110001312314 is an equidigital number, since it uses as much as digits as its factorization.

110001312314 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 55000656159.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 110001312314 its reverse (413213100011), we get a palindrome (523214412325).

The spelling of 110001312314 in words is "one hundred ten billion, one million, three hundred twelve thousand, three hundred fourteen".