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110001314342 = 255000657171
BaseRepresentation
bin110011001110010010…
…1101101101000100110
3101111221011212202022102
41212130211231220212
53300240314024332
6122311153532102
710642635513233
oct1463445555046
9344834782272
10110001314342
1142718968647
121939b274032
13a4b086a21a
14547744678a
152cdc2a7062
hex199c96da26

110001314342 has 4 divisors (see below), whose sum is σ = 165001971516. Its totient is φ = 55000657170.

The previous prime is 110001314309. The next prime is 110001314347. The reversal of 110001314342 is 243413100011.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 243413100011 = 1082932247727.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (110001314347) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27500328584 + ... + 27500328587.

It is an arithmetic number, because the mean of its divisors is an integer number (41250492879).

Almost surely, 2110001314342 is an apocalyptic number.

110001314342 is a deficient number, since it is larger than the sum of its proper divisors (55000657174).

110001314342 is an equidigital number, since it uses as much as digits as its factorization.

110001314342 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 55000657173.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 110001314342 its reverse (243413100011), we get a palindrome (353414414353).

The spelling of 110001314342 in words is "one hundred ten billion, one million, three hundred fourteen thousand, three hundred forty-two".

Divisors: 1 2 55000657171 110001314342