110001322320120 has 384 divisors, whose sum is σ = 445910303854080. Its totient is φ = 22847640192000.

The previous prime is 110001322320119. The next prime is 110001322320143. The reversal of 110001322320120 is 21023223100011.

110001322320120 is a `hidden beast` number, since 1 + 1 + 0 + 0 + 0 + 1 + 322 + 320 + 1 + 20 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 110001322320093 and 110001322320102.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 64044955 + ... + 65740085.

It is an arithmetic number, because the mean of its divisors is an integer number (1161224749620).

Almost surely, 2^{110001322320120} is an apocalyptic number.

110001322320120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 110001322320120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (222955151927040).

110001322320120 is an abundant number, since it is smaller than the sum of its proper divisors (335908981533960).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

110001322320120 is a wasteful number, since it uses less digits than its factorization.

110001322320120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1697507 (or 1697500 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 110001322320120 its reverse (21023223100011), we get a palindrome (131024545420131).

The spelling of 110001322320120 in words is "one hundred ten trillion, one billion, three hundred twenty-two million, three hundred twenty thousand, one hundred twenty".