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1100013300227 is a prime number
BaseRepresentation
bin10000000000011101111…
…001101110101000000011
310220011022211002111012202
4100000131321232220003
5121010311401101402
62201201130343415
7142321232530502
oct20003571565003
93804284074182
101100013300227
11394570915716
1215923428ab6b
137c96678402a
143b35316a839
151d931c2bb02
hex1001de6ea03

1100013300227 has 2 divisors, whose sum is σ = 1100013300228. Its totient is φ = 1100013300226.

The previous prime is 1100013300187. The next prime is 1100013300247. The reversal of 1100013300227 is 7220033100011.

It is an a-pointer prime, because the next prime (1100013300247) can be obtained adding 1100013300227 to its sum of digits (20).

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1100013300227 - 224 = 1099996523011 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1100013300199 and 1100013300208.

It is not a weakly prime, because it can be changed into another prime (1100013300247) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550006650113 + 550006650114.

It is an arithmetic number, because the mean of its divisors is an integer number (550006650114).

Almost surely, 21100013300227 is an apocalyptic number.

1100013300227 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100013300227 is an equidigital number, since it uses as much as digits as its factorization.

1100013300227 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 252, while the sum is 20.

Adding to 1100013300227 its reverse (7220033100011), we get a palindrome (8320046400238).

The spelling of 1100013300227 in words is "one trillion, one hundred billion, thirteen million, three hundred thousand, two hundred twenty-seven".