11000133113 has 4 divisors (see below), whose sum is σ = 11005048320. Its totient is φ = 10995217908.

The previous prime is 11000133043. The next prime is 11000133121. The reversal of 11000133113 is 31133100011.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31133100011 = 13 ⋅2394853847.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11000133113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11000133413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2454245 + ... + 2458722.

It is an arithmetic number, because the mean of its divisors is an integer number (2751262080).

Almost surely, 2^11000133113 is an apocalyptic number.

It is an amenable number.

11000133113 is a deficient number, since it is larger than the sum of its proper divisors (4915207).

11000133113 is an equidigital number, since it uses as much as digits as its factorization.

11000133113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4915206.

The product of its (nonzero) digits is 27, while the sum is 14.

Adding to 11000133113 its reverse (31133100011), we get a palindrome (42133233124).

The spelling of 11000133113 in words is "eleven billion, one hundred thirty-three thousand, one hundred thirteen".