1100014443313 has 4 divisors (see below), whose sum is σ = 1107299307328. Its totient is φ = 1092729579300.

The previous prime is 1100014443193. The next prime is 1100014443349. The reversal of 1100014443313 is 3133444100011.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1100014443313 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1100014443613) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3642431781 + ... + 3642432082.

It is an arithmetic number, because the mean of its divisors is an integer number (276824826832).

Almost surely, 2^{1100014443313} is an apocalyptic number.

It is an amenable number.

1100014443313 is a deficient number, since it is larger than the sum of its proper divisors (7284864015).

1100014443313 is an equidigital number, since it uses as much as digits as its factorization.

1100014443313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7284864014.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 1100014443313 its reverse (3133444100011), we get a palindrome (4233458543324).

The spelling of 1100014443313 in words is "one trillion, one hundred billion, fourteen million, four hundred forty-three thousand, three hundred thirteen".