110002023300101 has 4 divisors (see below), whose sum is σ = 110004221939532. Its totient is φ = 109999824660672.

The previous prime is 110002023300067. The next prime is 110002023300161. The reversal of 110002023300101 is 101003320200011.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 54681972615076 + 55320050685025 = 7394726^2 + 7437745^2 .

It is a cyclic number.

It is not a de Polignac number, because 110002023300101 - 2¹⁴ = 110002023283717 is a prime.

It is a super-3 number, since 3×110002023300101³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (110002023300161) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1099244666 + ... + 1099344731.

It is an arithmetic number, because the mean of its divisors is an integer number (27501055484883).

Almost surely, 2^{110002023300101} is an apocalyptic number.

It is an amenable number.

110002023300101 is a deficient number, since it is larger than the sum of its proper divisors (2198639431).

110002023300101 is an equidigital number, since it uses as much as digits as its factorization.

110002023300101 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2198639430.

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 110002023300101 its reverse (101003320200011), we get a palindrome (211005343500112).

The spelling of 110002023300101 in words is "one hundred ten trillion, two billion, twenty-three million, three hundred thousand, one hundred one".