Base | Representation |
---|---|
bin | 1010000000010010111110… |
… | …1011001101001000111111 |
3 | 1102221121110121212200101012 |
4 | 2200010233223031020333 |
5 | 2420211413020201343 |
6 | 35221232140105435 |
7 | 2213511325412012 |
oct | 240045753151077 |
9 | 42847417780335 |
10 | 11000211100223 |
11 | 3561188433704 |
12 | 1297ab853527b |
13 | 61a414096927 |
14 | 2a05ad607379 |
15 | 141219ea7718 |
hex | a012facd23f |
11000211100223 has 2 divisors, whose sum is σ = 11000211100224. Its totient is φ = 11000211100222.
The previous prime is 11000211100217. The next prime is 11000211100261. The reversal of 11000211100223 is 32200111200011.
11000211100223 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11000211100223 - 226 = 11000143991359 is a prime.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 11000211100198 and 11000211100207.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11000211105223) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500105550111 + 5500105550112.
It is an arithmetic number, because the mean of its divisors is an integer number (5500105550112).
Almost surely, 211000211100223 is an apocalyptic number.
11000211100223 is a deficient number, since it is larger than the sum of its proper divisors (1).
11000211100223 is an equidigital number, since it uses as much as digits as its factorization.
11000211100223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 11000211100223 its reverse (32200111200011), we get a palindrome (43200322300234).
The spelling of 11000211100223 in words is "eleven trillion, two hundred eleven million, one hundred thousand, two hundred twenty-three".
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