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11000211100217 is a prime number
BaseRepresentation
bin1010000000010010111110…
…1011001101001000111001
31102221121110121212200100222
42200010233223031020321
52420211413020201332
635221232140105425
72213511325412003
oct240045753151071
942847417780328
1011000211100217
1135611884336a9
121297ab8535275
1361a414096921
142a05ad607373
15141219ea7712
hexa012facd239

11000211100217 has 2 divisors, whose sum is σ = 11000211100218. Its totient is φ = 11000211100216.

The previous prime is 11000211100211. The next prime is 11000211100223. The reversal of 11000211100217 is 71200111200011.

It is a balanced prime because it is at equal distance from previous prime (11000211100211) and next prime (11000211100223).

It can be written as a sum of positive squares in only one way, i.e., 8416125915136 + 2584085185081 = 2901056^2 + 1607509^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11000211100217 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11000211100195 and 11000211100204.

It is not a weakly prime, because it can be changed into another prime (11000211100211) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500105550108 + 5500105550109.

It is an arithmetic number, because the mean of its divisors is an integer number (5500105550109).

Almost surely, 211000211100217 is an apocalyptic number.

It is an amenable number.

11000211100217 is a deficient number, since it is larger than the sum of its proper divisors (1).

11000211100217 is an equidigital number, since it uses as much as digits as its factorization.

11000211100217 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 28, while the sum is 17.

Adding to 11000211100217 its reverse (71200111200011), we get a palindrome (82200322300228).

The spelling of 11000211100217 in words is "eleven trillion, two hundred eleven million, one hundred thousand, two hundred seventeen".