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11000211133 is a prime number
BaseRepresentation
bin10100011111010100…
…11110011010111101
31001101121211121212011
422033222132122331
5140012023224013
65015312411221
7536411152252
oct121752363275
931347747764
1011000211133
11473537248a
12216bb46b11
131063c9c792
14764d27429
15445ad1c3d
hex28fa9e6bd

11000211133 has 2 divisors, whose sum is σ = 11000211134. Its totient is φ = 11000211132.

The previous prime is 11000211119. The next prime is 11000211137. The reversal of 11000211133 is 33111200011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10253992644 + 746218489 = 101262^2 + 27317^2 .

It is an emirp because it is prime and its reverse (33111200011) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11000211133 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11000211137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500105566 + 5500105567.

It is an arithmetic number, because the mean of its divisors is an integer number (5500105567).

Almost surely, 211000211133 is an apocalyptic number.

It is an amenable number.

11000211133 is a deficient number, since it is larger than the sum of its proper divisors (1).

11000211133 is an equidigital number, since it uses as much as digits as its factorization.

11000211133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 11000211133 its reverse (33111200011), we get a palindrome (44111411144).

The spelling of 11000211133 in words is "eleven billion, two hundred eleven thousand, one hundred thirty-three".